The rate of hydrate formation for the given c | vedclass

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(C) The rate of hydrate formation depends on the electrophilicity of the carbonyl carbon. Greater electrophilicity leads to a faster rate of nucleophi

Vedclass · Accepted Answer

$II > I > III$

Vedclass · Answer

(C) The rate of hydrate formation depends on the electrophilicity of the carbonyl carbon. Greater electrophilicity leads to a faster rate of nucleophilic addition. Electrophilicity is decreased by electron-donating groups (like $-CH_3$) and increased by steric hindrance reduction. Compound $II$ is formaldehyde $(HCHO)$,which has no electron-donating groups and minimal steric hindrance. Compound $I$ is acetaldehyde $(CH_3CHO)$,which has one electron-donating methyl group. Compound $III$ is acetone $((CH_3)_2CO)$,which has two electron-donating methyl groups and greater steric hindrance. Therefore,the order of reactivity is $II > I > III$.

The rate of hydrate formation for the given compounds is:

Similar Questions

What is meant by the following terms? Give an example of the reaction in each case.
$(i)$ Cyanohydrin
$(ii)$ Acetal
$(iii)$ Semicarbazone
$(iv)$ Aldol
$(v)$ Hemiacetal
$(vi)$ Oxime
$(vii)$ Ketal
$(viii)$ Imine
$(ix)$ $2,4-DNP$ derivative
$(x)$ Schiff's base

Acetal or ketal is:

Which statement is correct for product '$X$'?
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In which of the following groups does each member give a positive iodoform test?

Identify the products $A$,$B$,and $C$ in the following reaction sequence:
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$A \xrightarrow[(ii) H_3O^+, \Delta]{(i) (CH_3CO)_2O/CH_3COONa} C$

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